# orm/26N1RyhPb9S4.xml.gz
# ro/26N1RyhPb9S4.xml.gz
(src)="1"> amma gaafii 71ffaa irra jirra . kan gaafatamne , fraakshinii kamtu kanaan wajji wal qixa isa jedhu 3x / 5 hiruu x+4/ x+2 ? karaan gabaabaan , isa jala jiru ( denominator ) sun haa addaan furree fooyyeeysinuu . kanaafuu kan 3x/ 5 cufuma isaanif denominator argamsiisuun dirqama ykn karaa nuuf fooyyeeysa . denominatorri walii galaa cufaa isanii 4 dha . kanaafuu , yoo denominatori nuti qabnu 4 tahe ,, x/ 4 n kun dhugumatti x/ 4 . x/ 2 n kunilleen 2x/ 4 waliiin waanuma takkittiidha . ammallee ada 'uun 2x/ 4 kuniis kanuma waliin tokko .
(trg)="2"> Suntem la problema 71 .
(trg)="3"> Si ne intreaba , care fractie este egala cu acest lucru , 3x pe 5 impartit la x pe 4 plus x pe 2 ?
(trg)="4"> Acum cel mai bun mod de a face acest lucru , e sa simplificam numitorul mai intai .
(src)="2"> 2x/ 4 kuniis x/ 2 waliin tokkuma . ergasii amma yoo hirte firaakshinii tahe tokkoon , kuni akkasumatti heddummeeysuu wajjiiniis tokkuma taha , ( inverse ) ykn garagalchaa yoo tahullee . kanaafuu kuni 3x/ 5 wajjiin walqaixa tahuuf deema yoo heddemmeeysinu garagalchaadhaan ykn ( inverse ) suniin kan kanaa , heddummeeysuu 4/ x +2x
(trg)="10"> 2x pe 4 este acelasi lucru ca si x/ 2 .
(trg)="11"> Si acum daca imparti la o anumita fractie , e acelasi lucru ca inmultirea cu inversul sau .
(trg)="12"> Deci va fi egal cu 3x pe 5 inmultit cu inversul , 4 pe x plus 2x .
(src)="3"> Mee haa laalluu waan godhuu dandeenyu .
(trg)="13"> Sa vedem ce putem face .
(src)="4"> Eegaa , x kana asitti fooyyeeysuu dandeenya .
(trg)="14"> Putem sa scoatem factor comun x .
(src)="5"> Kanaafuu , x baayyisuu 1 dabaluu 2 .
(trg)="15"> Deci x inmultit cu 1 plus 2 .