# da/DBaXxI3c9Zvk.xml.gz
# yor/DBaXxI3c9Zvk.xml.gz
(src)="1"> When you smile , your lips
(trg)="1"> When you smile ...
(src)="2"> look like a rosebud .
(trg)="2"> Your lips are like rosebud .
(src)="3"> I liked your lips ... ... and you liked roses .
(trg)="3"> I like your lips ... ... but you liked rose .
(src)="4"> I liked your lips ... ... and you liked roses .
(trg)="4"> I liked your libs ... ... but you liked roses .
(src)="5"> Roses and lips tell ... ... an old love that is ... ... how hurt and mystic now .
(trg)="5"> Roses and libs, now ... ... what a pain and secret !
(trg)="6"> They tell an old love .
(src)="6"> Roses and lips .
(trg)="7"> Roses and lips , now
(src)="7"> Rose and lips tell ... ... an old love that is ... ... how hurt and mystic now .
(trg)="8"> Roses and lips , now ... what a pain abd secret .
(trg)="9"> They tell an old love
(src)="8"> Roses and lips .
(trg)="10"> Roses and lips
(src)="9"> My leaves fall down ... ... to garden that called in my memory .
(trg)="11"> My leafs falled into ... ... a garden that is called my past .
(src)="10"> My lips got lost ... ... nobody loves roses now .
(trg)="12"> My lips lost .
(trg)="13"> Nobady likes roses after that
(src)="11"> My lips got lost ... ... nobody loves roses now .
(trg)="14"> My lips lost .
(trg)="15"> Nobady likes roses after that .
(src)="12"> Roses and lips tell ... ... an old love that is ... ... how hurt and mystic now .
(trg)="16"> Roses and lips , now ... ... what a pain and secret ...
(src)="13"> Roses and lips .
(src)="14"> Roses and lips tell ... .... an old love that is ... ... how hurt and mystic now .
(trg)="17"> They tell an old love . ... roses and lips , now ... roses and lips , now ... ... what a pain and secret ...
(src)="15"> Roses and lips .
(trg)="18"> They tell an old love ... ... roses and lips
# da/WVL2qxNoFdCC.xml.gz
# yor/WVL2qxNoFdCC.xml.gz
(src)="2"> Vi er på problem 14
(trg)="1"> A wa ni apa merinla .
(src)="3"> Og dette spørger os om hvad solutionen på uligheden af x er . minus 5 er større en 14 ? til at gøre dette er ligsom at løse den . enhver lighed eller ligning .
(trg)="2"> O de so fun wa pe , ki ni iwa di inequality x yo kuro marun ninu merinla ?
(trg)="3"> Ta ba fe she eleyi , o da bi equality ta bi equation . nkan ta ba se si apa kan , a gbodo se si apa keji .
(src)="5"> Og vi ønsker at slippe af med dette " minus 5 " , og den bedste måde at slippe af et minus 5 at tilføje 5 , så lad os tilføje 5 på begge sider i denne ligning .
(src)="6"> Så 5 og derefter et plus 5 .
(src)="7"> Og derefter en 5 minus 5 , det er 0 .
(trg)="4"> A fe yo marun yi kuro , ona ta ma fi se ni ka yo marun , ka si fi marun pada si apa kan na ise yi . pa marun po ati marun mi . marun , yo marun , a fun wa ni odo . nkan ta fi marun ni ibeere ni yen . x lo ku ni apa yen .
(src)="10"> Vi får " x er større end 14 plus 5 " , som er 19 .
(src)="11"> Der er valg :
(src)="12"> B.
(trg)="5"> A ni x ju merinla fi marun kun , a di mokandilogun . eyin ni B .
(src)="13"> Problem nummer 15 .
(src)="14"> Længderne af siderne i en trekant er -- så vi har en trekant .
(trg)="6"> Apa medogun . oke ati isale triangle ni a ni triangle .
(src)="15"> De fortæller os , længderne af siderne er y , y plus 1 , og 7 centimeter .
(trg)="7"> O so fun wa pe oke ati isale ni y , y pelu okan ati meje centimeters .
(src)="16"> De fortæller os også , omkredsen er 56 cm .
(trg)="8"> O tun so fun wa pe perimeter ni merindilogota centimeters .
(src)="17"> Omkredsen er lig med 56 centimeter .
(trg)="9"> Perimeter a wa je merindilogota centimeters .
(src)="18"> Hvad er værdien af y ?
(trg)="10"> Ki ni y ?
(src)="19"> Så er omkredsen af en vilkårlig figur blot summen af sider .
(src)="20"> Så y plus y plus 1 plus 7 .
(trg)="11"> Eyi tumo si pe perimeter ni ipawopo y pelu y pelu okan pelu meje .